Question 1007231: in a class of 147 students, 95 are taking math(M) 73 are taking science(S), and 52 are taking both math and science. if one student is picked at random, what is the probability of choosing a student who is NOT taking math or science?
I don't understand how this could be possible. Please help!
My answer choices are 52/147, 73/147, 31/147, and 125/147.
Thank you!
Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! If 95 are taking math and 52 are taking math AND science, then 43 are just taking math.
If 73 are taking science and 52 are taking math AND science, then 21 are just taking science.
Now add 43 + 21 + 52 = 116 students taking either or both math and science.
If there are 147 students, then
147 - 116 = 31 are not taking either.
31/147 is the answer.
|
|
|