Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 1210440: The probability of a dry day is
2°
5
If it is a dry day, the probability that Sonia cycles to work is
3
17, that she drives to work is
17' and that
9
she takes the train to work is
17°
If it is a wet day, the probability that Sonia cycles to work is , that she drives to work is
3, and that she
takes the train to work is
3 • Determine the probability that Sonia takes the train to work.
(Create a tree diagram to help you)
You may enter a calculation that leads to your answer
Click here to see answer by ikleyn(52967)   |
Question 1210439: Trey wakes up late on average 4 days out of every 5. If Trey wakes up late, the probability that he is late for school is 90%. If Trey doesn't wake up late the probability that he is late for school is 25%. Create a tree diagram by entering the percentages and then calculate the percent chance that Trey gets to school on time.
Enter your answers as a decimal or fraction between 0 and 1.
Click here to see answer by ikleyn(52967) |
Question 1210441: Giving a test to a group of students, the grades and gender are summarized below
A B C Total
Male 12 39 17 68
Female 16 11 33 60
Total 28 50 50 128
If one student is chosen at random,
Find the probability that the student was female GIVEN they got a 'A.
Click here to see answer by ikleyn(52967) |
Question 1210434: A CBS News poll conducted June 10 and 11, 2006, among a nationwide random sample of 651 adults, asked those adults about their party affiliation (Democrat, Republican or none) and their opinion of how the US economy was changing (getting better," "getting worse" or "about the same"). The results are shown in the table below.
better same worse
Republican 38 104 44
Democrat 12 87 137
none 21 90 118
Express your answers as a decimal and round to the nearest 0.001 (in other words, type 0.123, not 12.3% or 0.123456).
If we randomly select one of the adults who participated in this study, compute:
a. P(Democrat) =
b. P(better) =
c. P(better | Democrat) =
d. P(Democrat | better) =
e. P(Democrat and better) =
Click here to see answer by ikleyn(52967) |
Question 1210436: Round each answer to at least 4 decimal places accuracy.
Owen, the inventory manager at a company's distribution center, records the following inventory for a beach towel that comes in two sizes (large or small) and three colors (Green, Black, and Yellow).
Green Black Yellow Total
Large 18 5 3 26
Small 7 13 2 22
Total 25 18 5 48
a. If Owen selects one beach towel at random, what is the probability that the beach towel is Black or Yellow?
Drive
65
oach
Climate
b. If Owen selects one beach towel at random, what is the probability that it is Small, given that it is Green?
c. If Owen selects one beach towel at random, what is the probability that the beach towel is Black or that it is Large?
d. If Owen selects one beach towel at random, Find P(Black)?
Click here to see answer by n2(8) |
Question 1210431: 28
A certain virus infects one in every 600 people. A test used to detect the virus in a person is positive 90% of the time if the person has the virus and 10% of the time if the person does not have the virus. Give your answer as a decimal to 4 decimal places.
(a) Find the probability that a person has the virus given that they have tested positive.
(b) Find the probability that a person does not have the virus given that they have tested negative.
Click here to see answer by math_tutor2020(3822) |
Question 1210432: A CBS News poll conducted June 10 and 11, 2006, among a nationwide random sample of 651 adults, asked those adults about their party affiliation (Democrat, Republican or none) and their opinion of how the US economy was changing (getting better," "getting worse" or "about the same"). The results are shown in the table below.
better same worse
Republican 38 104 44
Democrat 12 87 137
none 21 90 118
Express your answers as a decimal and round to the nearest 0.001 (in other words, type 0.123, not 12.3% or 0.123456).
If we randomly select one of the adults who participated in this study, compute:
P (Democrat) =
P(same) =
P(Democrat and same) =
Click here to see answer by ikleyn(52967) |
Question 1210424: A CBS News poll conducted June 10 and 11, 2006, among a nationwide random sample of 651 adults, asked those adults about their party affiliation (Democrat, Republican or none) and their opinion of how the US economy was changing ("getting better," "getting worse" or "about the same"). The results are shown in the table below. Express your answers as a decimal and round to the nearest 0.001 (in other words, type 0.123, not 12.3% or 0.123456).
If we randomly select one of the adults who participated in this study, compute:
P(Democrat)=
P(same)=
P(Democrat and same)=
Click here to see answer by ikleyn(52967) |
Question 1210424: A CBS News poll conducted June 10 and 11, 2006, among a nationwide random sample of 651 adults, asked those adults about their party affiliation (Democrat, Republican or none) and their opinion of how the US economy was changing ("getting better," "getting worse" or "about the same"). The results are shown in the table below. Express your answers as a decimal and round to the nearest 0.001 (in other words, type 0.123, not 12.3% or 0.123456).
If we randomly select one of the adults who participated in this study, compute:
P(Democrat)=
P(same)=
P(Democrat and same)=
Click here to see answer by math_tutor2020(3822) |
Question 1210426: Amber rolls a 6-sided die. On her first roll, she gets a "4". She rolls again.
(a) What is the probability that the second roll is also a "4".
P(4 | 4) =
(b) What is the probability that the second roll is a "2".
P(2 / 4) =
Click here to see answer by ikleyn(52967) |
Question 1210425: Sara draws the 3 of hearts from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card.
a. Determine the probability that the second card is another 3.
P(3 3 of hearts) =
b. Determine the probability that the second card is another heart.
P (heart 3 of hearts) =
c. Determine the probability that the second card is a club.
P (club 3 of hearts) =
d. Determine the probability that the second card is a 7.
P(7 / 3 of hearts) =
Write your answers as reduced fractions.
Click here to see answer by math_tutor2020(3822) |
Question 648024: "A student has to sit for an examination consisting of 3 questions selected randomly from a list of 100 questions. To pass, he should answer all the three questions. What is the probability that the student will pass the examination, if he knows the answer to 90 questions on the list."
I have asked this question before and i got the answer as .729 but its the wrong answer. I have also solved it the same but correct answer is .798 and i don't know how to get this one...?????????
Click here to see answer by ikleyn(52967) |
Question 625941: The probabilities that a batch of 4 computers will contain 0,1,2,3, and 4 defective computers are 0.6274, 0.3102, 0.0575, 0.0047, and 0.0001, respectfully. Find the standard deviation for the probability distribution.
Click here to see answer by ikleyn(52967) |
Question 629274: Different positive four-digit integers are to be formed by using each of the digits 1,2,3,4 just once in each integer. How many different such integers can be formed if the digits 3 and 4 must NEVER be next to each other?
A. 4
B. 8
C. 12
D. 16
E. 24
Click here to see answer by ikleyn(52967) |
Question 629744: There are three components that operate in a series so all must function properly if it is to be complete. The probability of failure during one period of operation are .03, .05, .06. Component failures are statistically independent.
a) Fine the probability that the system functions properly.
b) Find the probability that the system fails during one period of operation
This is what I have done so far but I'm not sure its the right answer please help me and show how you got to the answer so I understand
a) .97*.95*.94=.866
b)(.03+.05+.06)-(.03*.05*.06)=.14
Click here to see answer by ikleyn(52967) |
Question 614980: The independent probability of a passenger arriving for a booked flight on a Maxi service is 0.8. The airline booked 225 passengers and there are 195 seats available on Maxi..Use the Normal distribution to find the probability for a given flight more booked passengers arrive than there are seats available.
Click here to see answer by ikleyn(52967) |
Question 615732: The employees at a General Motors assembly plant are polled as they leave work. Each is asked, �What brand of automobile are you riding home in?� The random variable to be reported is the number of each brand mentioned. Is x a binomial random variable? Justify your answer.
Click here to see answer by ikleyn(52967) |
Question 202488: Can someone PLEASE help me with these? Thank You. :)
1) A person is wearing a bracelet with 11 settings around the bracelet. How many different ways can 11 birthstones be arranged around the bracelet? Leave the answer in factorial form.
2) How many subsets of four elements each exist in a set of seven elements?
3) How many different groups of 35 cars can be formed from 40 cars?
4) How many different ways can an executive committee of nine people sit at a round table?
5) What is the probability of not drawing a green marble from a jar containing 7 red, 4 green, 3 white, and 9 blue marbles?
6) A compound experiment consists of drawing at random twice without replacing from a jar with 3 red, 3 white, and 2 black marbles. What is the probability of getting first a red and then a black marble?
Thanks again,
~Sarah
Click here to see answer by ikleyn(52967) |
Question 585040: there are 3 boxes containing respectively 1 white, 2 red, 3 black balls; 2 white, 3 red, 1 black ball; 3 white, 1 red and 2 black balls. a box is chosen at random and from it two balls are drawn at random. the two balls are 1 red and 1 white. what is the probability that they come from (1) first box (11) second box (111) third box?
Click here to see answer by ikleyn(52967) |
Question 568292: Hi. Can you please help me with this question!!!
Sixty percent of a company's sales representatives have completed training seminars. Of these, 80 percent have had increased sales. Overall 56 percent (whether trained or not) have had increased sales. What's the probability of increased sales given that the representative has not been trained?
Click here to see answer by ikleyn(52967) |
Question 478361: ples please someone....I NEED HELP WITH THIS QUESTION I HAVE SUBMITTED IT SEVERAL TIMES THE FIRST TIME I DID NOT GIVE ALL OF THE INFORMATION, THE SECOND TIME I PUT IN THE WRONG EMAIL ADDRESS....I DESPERATELY NEED HELP WITH IT I DO NOT KNOW WHERE TO BEGIN AND CAN NOT FIND AN EXAMPLE THAT CAN GUIDE ME ALONG THE WAY SO THAT I WILL EVEN KNOW WHERE TO BEGIN....PLEASE HELP!!!! LET X BE A RANDOM VARIABLE WITH THE FOLLOWING PROBAILITY DISTRIBUTION
X 0 1 2 3
P(X) 0.4 0.3 0.2 0.1
DOES X HAVE A BINOMIAL DISTRIBUTION JUSTIFY YOUR ANSWER
Click here to see answer by ikleyn(52967) |
Question 483897: the probability that a bullet fired from a point will hit the target is 1/3. Three such bullets are fired simultaneously towards the target from that very point. What is the probability that the target will be hit?
Click here to see answer by ikleyn(52967) |
Question 488895: Can you please show steps how to calculate the profile score:
Student received 9/20 in maths, 8/20 in english, 16/30 in General Ability Test.
The school assessment marks were given as 80/100 - English, 87/100 - Maths.
The calculated profile score used a mean of 60 and standard deviation of 12.
The result was 199.99 as the profile score for the student.
Please show steps how this was calculated to get 199.99? Thanks.
Click here to see answer by ikleyn(52967) |
Question 488990: If I drop three coins on a table, what is the probability of finding
1. exactly 2 heads
2. at most 1 head
3. at least 2 heads
4. at least 1 head
sample space = 8
I came up with HHT, HTH, THH,HTT,THT,TTH,TTT,HHH.
state the probability of each in the form of fraction and percent.
For 1,2,3 I came up with 1/4 or .25, and for 4 = 1/6.
Have I done this correctly, or can you show me a better way to show this??
Is this a form of "classical probability"??
Thank you.
Click here to see answer by ikleyn(52967) |
Question 1166976: A special deck of cards has 10 green cards , 13 blue cards , and 5 red cards . When a card is picked, the color is recorded. An experiment consists of first picking a card and then tossing a coin.
a. How many elements are there in the sample space?
b. Let A be the event that a green card is picked first, followed by landing a head on the coin toss.
P(A) =
Round your answer to 4 decimal places.
c. Let B be the event that a red or blue is picked, followed by landing a head on the coin toss. Are the events A and B mutually exclusive?
- No, they are not Mutually Exclusive
-Yes, they are Mutually Exclusive
d. Let C be the event that a green or blue is picked, followed by landing a head on the coin toss. Are the events A and C mutually exclusive?
-No, they are not Mutually Exclusive
-Yes, they are Mutually Exclusive
Click here to see answer by CPhill(1987)  |
Question 1167102: The manager of the commercial mortgage department of a large bank has collected data during the past two years concerning the number of commercial mortgages approved per week. The results from these two years (104 weeks) are shown to the right.
a. Compute the expected number of mortgages approved per week.
b. Compute the standard deviation.
c. What is the probability that there will be more than one commercial mortgage approved in a given week?
Number Approved , Frequency
0, 13
1, 25
2,33
3, 16
4, 8
5, 6
6 ,2
7, 1
a. The expected number of mortgages approved per week is
Click here to see answer by CPhill(1987) |
Question 1167196: Por favor que alguien me ayude a resolver este ejercicio.
Una facultad de contaduría de la capital funciona en tres jornadas: mañana, tarde y noche. En un grupo de estudiantes que finalizan la carrera, se encuentran que el 25 % egresan de la jornada diurna, el 15% de la jornada tarde y el restante 60% de la jornada nocturna. Un 14% de los egresados de la mañana se graduó por promedio de calificación exigida por la facultad, un 8% de la tarde y un 22% de la nocturna. ¿Cuál es la probabilidad, al realizar la selección de un estudiante graduado por alcanzar promedio exigido, de que este provenga de la jornada diurna?
Click here to see answer by CPhill(1987) |
Question 1167253: Una facultad de contaduría de la capital funciona en tres jornadas: mañana, tarde y noche. En un grupo de estudiantes que finalizan la carrera, se encuentran que el 25 % egresan de la jornada diurna, el 15% de la jornada tarde y el restante 60% de la jornada nocturna. Un 14% de los egresados de la mañana se graduó por promedio de calificación exigida por la facultad, un 8% de la tarde y un 22% de la nocturna. ¿Cuál es la probabilidad, al realizar la selección de un estudiante graduado por alcanzar promedio exigido, de que este provenga de la jornada diurna?
Click here to see answer by CPhill(1987) |
Question 1167319: )
A brewery has a beer dispensing machine that dispenses beer into the company's 12 ounce
bottles. The distribution for the amount of beer dispensed by the machine follows a normal
distribution with a standard deviation of 0.19 ounce. The company can control the mean
amount of beer dispensed by the machine. What value of the mean should the company
use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount
on the label)? Round to the nearest thousandth.
Click here to see answer by CPhill(1987) |
Question 1167440: A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a 87.78% confidence interval. The blood cholesterol level of young men follows a Normal distribution with standard deviation σ = 15 mg/dl. How large a sample would the researcher need to take to estimate the mean blood cholesterol to within 5 mg/dl?
A sample of at least __ people.
Click here to see answer by CPhill(1987) |
Question 1167453: I tried this problem but I ended up with different answers, and I confused myself. If you can understand this problem, you're a genius! But really, help is greatly appreciated. I'm not sure what I am doing with this problem. Am I finding the numbers that add up to the total? Again, any help is greatly appreciated!
A large corporation has 10,000 employees that were told to take a drug test. Research shows that the test is known to be 99% effective (that is, 99% of illegal drug users will test positive). The test is also known to have a false positive rate of 2% (that is, 2% of the time those employees who test positive are not drug users). The same. Suppose that 1% of the employees in the company used illegal drugs
Employee uses illegal drugs
Tests Positive:
Tests Negative:
Total:100
Employee does not use illegal drugs
tests positive: 198
tests negative:
Total: 9900
Overall total: 10000
What is the probability that a random employee is an illegal drug user and tests positive?
What is the probability that an employee tests positive, given the employee uses illegal drugs?
What is the probability that an employee uses illegal drugs, given the employee tests positive?
Click here to see answer by CPhill(1987) |
Question 1167504: Suppose you are representing the employees at a large corporation during contract negotiations. You have a list of the salaries of all the employees at the corporation (The salaries include the many lower level employees and the few high paid management employees) and you plan to find a measure of center (e.g. mean, median, or mode).
a. Which measure or center would you use to represent the employees in an effort to support your claim that the average salary of lower level employees is much lower than the national average (for lower level employees) and thus should be increased?
1.median
2.mean
3.mode
b. Why is this the better choice?
Click here to see answer by CPhill(1987) |
Question 1167512: The results of the latest writing of the LSAT (Law School Aptitude Test) showed results that were normally distributed with a mean score of 826 and a standard deviation of 50.
For part (d) enter probability answers in decimal form (i.e. 0.0003 instead of 0.0300 %
). Round the final answer to 4 decimals.
c)If a group of 59 applicants is randomly selected, what is the probability that the group average is not less than 846?
Click here to see answer by CPhill(1987) |
Question 1167569: Given the following data for an imaginary superhero universe:
Flying Telepathy Super Strength
Female 98 58 49
Male 96 80 56
Distribution of Super Power by Gender
What is the empirical probability that a randomly selected female superhero will have Super Strength?
Answer in decimal form. Round to 3 decimal places as needed
Click here to see answer by CPhill(1987) |
Question 1167570: Given the following data for an imaginary superhero universe:
Flying Telepathy Super Strength
Female 89 46 12
Male 35 38 82
Distribution of Super Power by Gender
What is the empirical probability that a randomly selected superhero will have super strength?
Answer in decimal form. Round to 3 decimal places as needed
Click here to see answer by CPhill(1987) |
Question 1167571: Given the following data for an imaginary superhero universe:
Flying Telepathy Super Strength
Female 78 24 7
Male 83 40 46
Distribution of Super Power by Gender
What is the empirical probability that a randomly selected superhero will have telepathy?
Answer in decimal form. Round to 3 decimal places as needed
Click here to see answer by CPhill(1987) |
Question 1167588: Textbook prices have a seasonal structure on Ebay. At the end of a term, the supply of used books outstrips demand, and the price is lower. Near the start of a term, many students are looking for books, and the price is higher. Suppose we can classify sales for a particular chemistry textbook into these two time periods and an "other" time period in the proportions shown below. We have also listed the average price the textbook sells for in each of these three time periods
Start-of-term End-of-term Other
Sales proportion 0.45 0.31 0.24
Average price $82.52 $49.12 $65.23
For example, about 45% of Ebay auctions for this chemistry textbook occur at the start of the term and the books sell for an average of $82.52 during this time. Using the information above, compute the average price of the textbook over all seasons
Click here to see answer by CPhill(1987) |
Question 1167602: Following table displays the number of days to maturity for 40 short-term investments.
77,64,99,55,64,89,87,65,62,38,67,70,60,69,78,39,75,56,71,51,68,95,57,53,47,50,55,81,80,98,51,36,63,66,85,79,83,70,99,78.
required: A)construct frequency distribution of size 10.
B)construct histogram.
Click here to see answer by CPhill(1987) |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 14356..14400, 14401..14445, 14446..14490, 14491..14535, 14536..14580, 14581..14625, 14626..14670, 14671..14715, 14716..14760, 14761..14805, 14806..14850, 14851..14895, 14896..14940, 14941..14985, 14986..15030, 15031..15075, 15076..15120, 15121..15165, 15166..15210, 15211..15255, 15256..15300, 15301..15345, 15346..15390, 15391..15435, 15436..15480, 15481..15525, 15526..15570, 15571..15615, 15616..15660, 15661..15705, 15706..15750, 15751..15795, 15796..15840, 15841..15885, 15886..15930, 15931..15975, 15976..16020, 16021..16065, 16066..16110, 16111..16155, 16156..16200, 16201..16245, 16246..16290, 16291..16335, 16336..16380, 16381..16425, 16426..16470, 16471..16515, 16516..16560, 16561..16605, 16606..16650, 16651..16695, 16696..16740, 16741..16785, 16786..16830, 16831..16875, 16876..16920, 16921..16965, 16966..17010, 17011..17055, 17056..17100, 17101..17145, 17146..17190, 17191..17235, 17236..17280, 17281..17325, 17326..17370, 17371..17415, 17416..17460, 17461..17505, 17506..17550, 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