SOLUTION: Write a polynomial division that has a quotient of x+3 and a remainder of 2

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Question 988690: Write a polynomial division that has a quotient of x+3 and a remainder of 2
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39632) About Me  (Show Source):
You can put this solution on YOUR website!
Pick some dividend (quadratic) and divisor (linear) and work with them. The remainder 2 will mean 2%2F%28x%2B-+k%29.

Pick anything but also try using some known constants.

Start as example maybe this way:
%28x%5E2%2B7x%2B5%29%2F%28x%2Bk%29=x%2B3%2B2%2F%28x%2Bk%29
See what you can find.

All that was a suggestion. I have not yet tried this myself. Maybe try dividend of x^2+4x+v for dividend and x+3 as divisor.

Answer by MathTherapy(10559) About Me  (Show Source):
You can put this solution on YOUR website!

Write a polynomial division that has a quotient of x+3 and a remainder of 2
First, choose a divisor, such as x + 1
Formula to form polynomial: %28D+%2A+Q+%2B+R%29%2FD, with:
D being the divisor
Q being the quotient, and
R being the remainder
With x + 1 being the chosen divisor, %28D+%2A+Q+%2B+R%29%2FD becomes:
%28%28x+%2B+1%29%28x+%2B+3%29+%2B+2%29%2F%28x+%2B+1%29
%28x%5E2+%2B+4x+%2B+3+%2B+2%29%2F%28x+%2B+1%29
Polynomial: highlight_green%28%28x%5E2+%2B+4x+%2B+5%29%2F%28x+%2B+1%29%29