SOLUTION: How to factorize it √3*x^2+11*x+6*√3 Sol: √3*x^2+2*x+9*x+6*√3 But then?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How to factorize it √3*x^2+11*x+6*√3 Sol: √3*x^2+2*x+9*x+6*√3 But then?      Log On


   

Question 978073: How to factorize it √3*x^2+11*x+6*√3
Sol: √3*x^2+2*x+9*x+6*√3
But then?
Found 3 solutions by Boreal, josgarithmetic, Edwin McCravy:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
√3*x^2+11*x+6*√3=
If you rewrite as sqrt (3) x^2 +2x + 9x +6 sqrt (3)
=x (x sqrt (3)+2) ;; +;; 3 sqrt(3) (x sqrt (3) +2)
=(x+3 sqrt (3))* {x sqrt (3) +2}
=x^2* sqrt(3) +2x+3x(sqrt(3)(sqrt(3) +6 sqrt (3)

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
After trying testing roots as for "Rational Roots Theorem", and also trying general solution for quadratic equation, the quadratic expression seems NOT factorable. Discriminant for that expression is -95, therefore the roots are not Real.

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Boreal's solution is better than the way I did it, so I deleted mine. :)