SOLUTION: Please help me factor the trinomials. {{{25x^2 -15x + 2}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me factor the trinomials. {{{25x^2 -15x + 2}}}       Log On


   



Question 964757: Please help me factor the trinomials.

25x%5E2+-15x+%2B+2

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
25x%5E2+-15x+%2B+2
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 25x%5E2%2B-15x%2B2+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-15%29%5E2-4%2A25%2A2=25.

Discriminant d=25 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--15%2B-sqrt%28+25+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-15%29%2Bsqrt%28+25+%29%29%2F2%5C25+=+0.4
x%5B2%5D+=+%28-%28-15%29-sqrt%28+25+%29%29%2F2%5C25+=+0.2

Quadratic expression 25x%5E2%2B-15x%2B2 can be factored:
25x%5E2%2B-15x%2B2+=+25%28x-0.4%29%2A%28x-0.2%29
Again, the answer is: 0.4, 0.2. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+25%2Ax%5E2%2B-15%2Ax%2B2+%29