SOLUTION: Express f(x) in the form f(x)=(x-k)q(x) + r for the given value of k f(x)=2x^3 +x^2 + x - 6, k=-1

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Express f(x) in the form f(x)=(x-k)q(x) + r for the given value of k f(x)=2x^3 +x^2 + x - 6, k=-1      Log On


   

Question 962920: Express f(x) in the form f(x)=(x-k)q(x) + r for the given value of k
f(x)=2x^3 +x^2 + x - 6, k=-1
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
k=-1 should be tested as a root using synthetic division.

-1_________|_____________________________
___________|
___________|
___________|_______2_________1_______1_______-6
___________|
___________|________________-2_______1_______-2______
__________________2_________-1_______2_______-8


f%28x%29=%28x-%28-1%29%29%282x%5E2-x%2B2%29%2B%28-8%29
f%28x%29=%28x%2B1%29%282x%5E2-x%2B2%29-8