SOLUTION: Hey I need help. The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show m

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hey I need help. The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show m      Log On


   

Question 961563: Hey I need help. The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show me step by step please.
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show me step by step please.
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(ab)^2 -ab - 6 = (ab-3)(ab+2)
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Width = ab+2
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Cheers,
Stan H.
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Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the area of a rectangle is given by a polynomial function
A%28x%29=a%5E2b%5E2-ab-6....we know that the area of a rectangle is is length%2A+width, so factor completely A%28x%29=a%5E2b%5E2-ab-6 and see if the +%28ab-3%29 is a factor; if it is a factor, then the other part will be the width

A%28x%29=a%5E2b%5E2-ab-6
A%28x%29=%28ab%29%5E2-ab-6....write -ab as 2ab-3ab
A%28x%29=%28ab%29%5E2%2B2ab-3ab-6...group
A%28x%29=%28%28ab%29%5E2%2B2ab%29-%283ab%2B6%29
A%28x%29=ab%28ab%2B2%29-3%28ab%2B2%29
A%28x%29=%28ab-3%29%28ab%2B2%29
since given that %28ab-3%29 is the length, then highlight%28ab%2B2%29 is the width