SOLUTION: How to find exact zeros of p(x)=x^4+7x^3+13x^2-3x-18

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Question 947961: How to find exact zeros of p(x)=x^4+7x^3+13x^2-3x-18
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Cx%5E4%2B7x%5E3%2B13x%5E2-3x-18%29
Looks like x=-3,x=-2, and x=1 are the zeros.
Verify plugging in the value,
%28-3%29%5E4%2B7%28-3%29%5E3%2B13%28-3%29%5E2-3%28-3%29-18=81-189%2B117%2B9-18=0
Verify that this is true for the remaining two values.