SOLUTION: The equation 5 x^4-7 x^3 - 2 x^2 = 0 has three real solutions A,B,C where A<B<C A=______ B=______ C=______

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The equation 5 x^4-7 x^3 - 2 x^2 = 0 has three real solutions A,B,C where A<B<C A=______ B=______ C=______      Log On


   

Question 930730: The equation 5 x^4-7 x^3 - 2 x^2 = 0 has three real solutions A,B,C where A A=______
B=______
C=______
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

5x%5E4-7x%5E3+-2x%5E2+=+0
x%5E2%285x%5E2-7x+-2%29+=+0
x%5E2%285x%5E2-7x+-2%29+=+0
solutions:
if x%5E2+=+0=> x=0-double solution
%285x%5E2-7x+-2%29+=+0 use quadratic formula
x+=+%28-%28-7%29+%2B-+sqrt%28+%28-7%29%5E2-4%2A5%2A%28-2%29+%29%29%2F%282%2A5%29+
x+=+%287+%2B-+sqrt%28+49%2B40+%29%29%2F10+
x+=+%287+%2B-+sqrt%28+89+%29%29%2F10+
exact solutions:
x+=+%287+%2B+sqrt%28+89+%29%29%2F10+
x+=+%287+-+sqrt%28+89+%29%29%2F10+

A=__0___
B=___%287+%2B+sqrt%28+89+%29%29%2F10+___
C=___+%287+-+sqrt%28+89+%29%29%2F10+___