SOLUTION: products of binominals. (3x-4)(6x+2) first the 3x(6x) then 3x(2) 2nd -4(6x) then -4(2) to get =18x^2+6x-24x-8 then the 6x(3x) then 6x(-4) next 2(3x) and 2(-4) =18x^2-24x+6x

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: products of binominals. (3x-4)(6x+2) first the 3x(6x) then 3x(2) 2nd -4(6x) then -4(2) to get =18x^2+6x-24x-8 then the 6x(3x) then 6x(-4) next 2(3x) and 2(-4) =18x^2-24x+6x      Log On


   

Question 92208: products of binominals.
(3x-4)(6x+2)
first the 3x(6x) then 3x(2) 2nd -4(6x) then -4(2) to get =18x^2+6x-24x-8
then the 6x(3x) then 6x(-4) next 2(3x) and 2(-4) =18x^2-24x+6x-8 i get lost at this point. this problem from a review sheet i have not from a book.
do i simplify 18x^2-24x+6x-8? do i -24x+6x=-18x
then i am left with 18x^2-18x-8 is this correct?

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the given expression

%283x-4%29%286x%2B2%29

When you FOIL, you multiply the terms in this order:
F-First (i.e. you multiply the first terms in each parenthesis which in this case are 3x and 3x)
O-Outer (i.e. you multiply the outer terms in each parenthesis which in this case are 3x and -4)
I-Inner (i.e. you multiply the inner terms in each parenthesis which in this case are -4 and 3x)
L-Last (i.e. you multiply the last terms in each parenthesis which in this case are -4 and -4)


So lets multiply the first terms:
3x%2A6x=18x%5E2 multiply 3x and 6x to get 18x%5E2



So lets multiply the outer terms:
3x%2A2=6x multiply 3x and 2 to get 6x



So lets multiply the inner terms:
-4%2A6x=-24x multiply -4 and 6x to get -24x



So lets multiply the last terms:
-4%2A2=-8 multiply -4 and 2 to get -8

Now lets put all the multiplied terms together
18x%5E2%2B6x-24x-8

Now combine like terms

18x%5E2-18x-8

So the expression

%283x-4%29%286x%2B2%29

FOILs to:

18x%5E2-18x-8