SOLUTION: How to find the leading coefficient of this polynomial:
H(x) = (2x+6)(x-3)^2(x+1)^3
x-int: (-3,0),(3,0),(-1,0)
y-int: (0,54)
I know the degree is 6 by adding the exponent
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-> SOLUTION: How to find the leading coefficient of this polynomial:
H(x) = (2x+6)(x-3)^2(x+1)^3
x-int: (-3,0),(3,0),(-1,0)
y-int: (0,54)
I know the degree is 6 by adding the exponent
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Question 916912: How to find the leading coefficient of this polynomial:
H(x) = (2x+6)(x-3)^2(x+1)^3
x-int: (-3,0),(3,0),(-1,0)
y-int: (0,54)
I know the degree is 6 by adding the exponents, right?
But how do I find the leading coefficient?
Please help
Thank you Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! One term of will occur when you multiply to get the product; no other terms of will occur, so you can find this leading term separately from the other terms containing x.
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