SOLUTION: Find the real solution by factoring X^4 = x^2 X to the fourth equals x to the second

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Question 895278: Find the real solution by factoring
X^4 = x^2
X to the fourth equals x to the second
Found 2 solutions by jim_thompson5910, harpazo:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E4=x%5E2

x%5E4-x%5E2=0

x%5E2%28x%5E2-1%29=0

x%5E2%28x%5E2-1%5E2%29=0

x%5E2%28x-1%29%28x%2B1%29=0

x%5E2=0 or x-1=0 or x%2B1=0

x=0 or x=1 or x=-1

The three solutions are x=0 or x=1 or x=-1

Answer by harpazo(655) About Me  (Show Source):
You can put this solution on YOUR website!
x^4 = x^2

x^4 - x^2 = 0

x^2(x^2 - 1) = 0

Set each factor to zero and solve for x.

x^2 = 0

Take the square root of both sides.

sqrt{x^2) = sqrt{0}

x = 0

Do the same thing to the other factor.

x^2 - 1 = 0
x^2 = 1

sqrt{x^2} = sqrt{1}

x = +1 and x = -1

The real SOLUTIONS are the following values for x: -1, 0 and 1.

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