SOLUTION: Kiran drove from Tortula to Cactus, a distance of 299 mi. She increased her speed by 18 mi/h for the 400 mi trip from Cactus to Dry Junction. If the total trip took 8 h, what was h

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Kiran drove from Tortula to Cactus, a distance of 299 mi. She increased her speed by 18 mi/h for the 400 mi trip from Cactus to Dry Junction. If the total trip took 8 h, what was h      Log On


   



Question 842998: Kiran drove from Tortula to Cactus, a distance of 299 mi. She increased her speed by 18 mi/h for the 400 mi trip from Cactus to Dry Junction. If the total trip took 8 h, what was her speed from Tortula to Cactus?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
__________________speed___________time_________distance
T to C_____________r______________(___)________299
C to J___________r+18_____________(___)________400
TOTAL______________________________8

r for rate or speed
t for time in hours
d for distance in miles
rt=d generally and we can use in the form solved for t to help find expressions for the missing times in the table.


__________________speed___________time_________distance
T to C_____________r______________299/r____________299
C to J___________r+18_____________400/(r+18)________400
TOTAL______________________________8


IMPORTANT EQUATION
highlight%28highlight_green%28299%2Fr%2B400%2F%28r%2B18%29=8%29%29

SOLVE FOR r.