SOLUTION: Freeport McMoran projects that in 2010 world grain supply will be 1.8 trillion metric tons and the supply will be only 3/4 of the world grain demand. What will world grain demand b

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Freeport McMoran projects that in 2010 world grain supply will be 1.8 trillion metric tons and the supply will be only 3/4 of the world grain demand. What will world grain demand b      Log On


   

Question 83420: Freeport McMoran projects that in 2010 world grain supply will be 1.8 trillion metric tons and the supply will be only 3/4 of the world grain demand. What will world grain demand be in 2010?
Found 3 solutions by rapaljer, stanbon, uma:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Supply = 3%2F4 Demand

1.8 Trillion = 3%2F4 Demand

Multiply both sides of the given equation by the reciprocal of 3/4, which is 4/3.
%284%2F3%29+%2A+1.8+=+%284%2F3%29%2A%283%2F4%29+Demand
+4%2A.6=++Demand
Demand = 2.4 Trillion tons.

R^2 at SCC

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Freeport McMoran projects that in 2010 world grain supply will be 1.8 trillion metric tons and the supply will be only 3/4 of the world grain demand. What will world grain demand be in 2010?
---------------
Let world demand in 2010 be "x".
EQUATION:
(3/4)x = 1.8 trillion metric tons
x = (4/3)1.8 trillion metric tons
x = 2.4 trillion metric tons
==============
Cheers,
Stan H.

Answer by uma(370) About Me  (Show Source):
You can put this solution on YOUR website!
Let the world grain demand in 2010 be x trillion metric tons
So the supply = (3/4)x
But the supply is given to be 1.8 trillion metric tons
==> (3/4)x = 1.8
==> x = 1.8 * (4/3) [multiplying by (4/3) on both the sides]
==> x = 2.4
Thus the world grain demand in 2010 = 2.4 trillion metric tons