SOLUTION: the polynominial X^3+6x^2+11x+6 has the factorization over the integers (x+a)(x+b) (x+c)

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Question 82359This question is from textbook algebra
: the polynominial X^3+6x^2+11x+6
has the factorization over the integers
(x+a)(x+b) (x+c) This question is from textbook algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
X^3+6x^2+11x+6
has the factorization over the integers
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Using synthetic division:
-1....1....6....11....6
........1....5.....6..|..0
This shows that when you divide x^3+6x^2+11x+6 by (x+1)
the Quotient is x^2+5x+6 and the Remainder =0
Then the Quotient is factorable into (x+3)(x+2)
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So the polynomial factors into (x=1)(x+2)(x+3)
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Cheers,
Stan H.