SOLUTION: c...
is this correct
it is two different fractions both fractions need to be multiplied.
multiply: (3x-30)/(x^2-4x) times (8x)/(10-x)
My answer: (-6)/(x)
PROBLEM #2
Si
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: c...
is this correct
it is two different fractions both fractions need to be multiplied.
multiply: (3x-30)/(x^2-4x) times (8x)/(10-x)
My answer: (-6)/(x)
PROBLEM #2
Si
Log On
Question 79097: c...
is this correct
it is two different fractions both fractions need to be multiplied.
multiply: (3x-30)/(x^2-4x) times (8x)/(10-x)
My answer: (-6)/(x)
PROBLEM #2
Simplify
(m^2)/(8) divdied by (m^5)/(16)
my answer: (2)/(m^4) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! multiply: (3x-30)/(x^2-4x) times (8x)/(10-x)
Factor where you can to get:
[3(x-10)/x(x-4)]
Cancel where you can to get:
[3/(x-4)]
Multiply to get:
[-24/(x-4)
====================
PROBLEM #2
Simplify
(m^2)/(8) divdied by (m^5)/(16)
Invert the denominator to get:
(m^2)/8 times 16/(m^5)
Cancel where you can to get:
2/(m^3)
================
Cheers,
Stan H.
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