SOLUTION: 1. (2x-3)(x+6) = (x-9)(x+2) 2. Solve and check (2x+3)(2x^2-5x-3) = 0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 1. (2x-3)(x+6) = (x-9)(x+2) 2. Solve and check (2x+3)(2x^2-5x-3) = 0      Log On


   

Question 78024: 1. (2x-3)(x+6) = (x-9)(x+2)
2. Solve and check
(2x+3)(2x^2-5x-3) = 0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%282x-3%29%28x%2B6%29+=+%28x-9%29%28x%2B2%29

2x%5E2%2B9x-18+=+x%5E2-7x-18 foil both sides

2x%5E2-x%5E2%2B9x%2B7x-18%2B18+=+0 Get all terms to one side

x%5E2%2B16x+=+0 Combine like terms
x%28x%2B16%29=0 factor out an x
Set each factor equal to zero
x=0
x%2B16=0
x=-16
So our answer is
x=0 or x=-16
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%282x%2B3%29%282x%5E2-5x-3%29+=+0
Set each factor equal to zero
2x%2B3=0
2x=-3
x=-3%2F2
2x%5E2-5x-3=0
Factor:
ERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'quadratic_factoring'.
Error occurred executing solver 'quadratic_factoring' .


%282x%2B1%29%28x-3%29=0
Now set each of these factors equal to zero
2x%2B1=0
2x=-1
x=-1%2F2
x-3=0
x=3
So our answers are:
x=-3%2F2 or x=-1%2F2 or x=3