SOLUTION: Find all zeros of f(x) = x^3 - 7x^2 + 17x - 15 if 2 + i is one of the zeros of f(x). (How does the zero product property play a role in solving this equation? I don't really under

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find all zeros of f(x) = x^3 - 7x^2 + 17x - 15 if 2 + i is one of the zeros of f(x). (How does the zero product property play a role in solving this equation? I don't really under      Log On


   



Question 773385: Find all zeros of f(x) = x^3 - 7x^2 + 17x - 15 if 2 + i is one of the zeros of f(x).
(How does the zero product property play a role in solving this equation? I don't really understand how to use the zero product property in this sense).

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Is the function, f(x) factorable for complex numbers? What do you know about the zero product rule? Let a and b be complex numbers. If a*b=0 then either a=0 or b=0 or a=b=0. a or b being complex or real makes no difference.

In any case, rely on rational roots theorem to try to find .... wait! If you KNOW that 2+i is one of the zeros, then you KNOW 2-i is also a zero of f(x). You then have only one more zero to find.
Now, you can try Rational Roots Theorem if you wish to. You might try plusorminus 1, 3, 5, or 15. Only one of them will be a root. Best though to work with the two given and known complex roots, simplify their combined expression, and then do polynomial division on the dividend f(x).

Look at %28x-%282%2Bi%29%29%28x-%282-i%29%29, multiply, simplify. That is one of the quadratic roots of f(x). This quadratic factor, ... is x%5E2-4x%2B5, after its simplifications.


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THIS PART EDITED...
Trying Rational Roots Theorem and synthetic division, one REAL root is +3, so one factor of f(x) is (x-3).
The synthetic division testing for root of +3, gave the quotient x%5E2-4x%2B5 without any remainder. The roots of x%5E2-4x%2B5 are in fact, 2%2Bi and 2-i. Seeing that can be found through general solution to quadratic formula.

FURTHER RECHECK:
In fact, x%5E3-7x%5E2%2B17x-15 divided by x%5E2-4x%2B5 DOES give quotient of x-3 without any remainder. Since 2%2Bi was given as one of the roots, this method would be the preferred method. x-3 is one of the factors of f(x).