SOLUTION: Please help me solve : 9x^3-3x^2-3x+1=0

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Question 770853: Please help me solve :
9x^3-3x^2-3x+1=0
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
9x%5E3-3x%5E2-3x%2B1=0 rearrange terms
9x%5E3-3x-3x%5E2%2B1+=+0.....group
%289x%5E3-3x%29-%283x%5E2-1%29+=+0....factor
3x%283x%5E2-1%29-%283x%5E2-1%29+=+0
%283x-1%29%283x%5E2-1%29+=+0

if %283x-1%29+=+0 then 3x=1 => x=1%2F3
if %283x%5E2-1%29+=+0 then 3x%5E2=1 => x%5E2=1%2F3=> x=sqrt%281%2F3%29
=> sqrt%281%2F3%29=1%2Fsqrt%283%29=>sqrt%283%29%2F3 or -sqrt%283%29%2F3
solutions:
x=1%2F3
sqrt%283%29%2F3
-sqrt%283%29%2F3
+graph%28+600%2C+600%2C+-5%2C+5%2C+-5%2C+10%2C+9x%5E3-3x%5E2-3x%2B1%29+