SOLUTION: {{{(2m^3x^2)^-1 (3m^4x)^-3/(m^2x^3)^3 (m^2x)^-5}}} Hi I need help solving this one. I am really stuck!!! I am not sure if I enterend the exponents properly? But the problem read

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: {{{(2m^3x^2)^-1 (3m^4x)^-3/(m^2x^3)^3 (m^2x)^-5}}} Hi I need help solving this one. I am really stuck!!! I am not sure if I enterend the exponents properly? But the problem read      Log On


   



Question 75660: %282m%5E3x%5E2%29%5E-1+%283m%5E4x%29%5E-3%2F%28m%5E2x%5E3%29%5E3+%28m%5E2x%29%5E-5
Hi I need help solving this one. I am really stuck!!! I am not sure if I enterend the exponents properly? But the problem reads:
(2m to the 3rd x to the 2nd)to the neg. 1 (3m to the 4th x) to the neg 3
divided by (m to the 2nd x to the 3rd) to the neg 3 (m to the 2nd x) to the neg 5th
Thank you in advance for any help that you can offer me.

Found 2 solutions by Cintchr, Earlsdon:
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
%282m%5E3x%5E2%29%5E-1+%283m%5E4x%29%5E-3%2F%28m%5E2x%5E3%29%5E-3+%28m%5E2x%29%5E-5
You only missed the negative sign on the exponent in the denominator.
Now, to solve it is easiest to deal with the negative exponents first. Anything that has a negative exponent jumps to the other side of the fraction and the exponent becomes positive.
For instance ...
+%287x%5E-3%29%2F%28-4y%5E-7%29+
now looks like ...
+%287y%5E7%29%2F%28-4x%5E3%29+
So, the problem you posed would now look like ....
+%28m%5E2x%5E3%29%5E3+%28m%5E2x%29%5E5+%2F+%282m%5E3x%5E2%29%5E1+%283m%5E4x%29%5E3+
Now deal with the exponents by applying the power to power. (multiply the exponents)
+%28m%5E6x%5E9%29%28m%5E10x%5E5%29+%2F+%282m%5E3x%5E2%29+%283%5E3m%5E12x%5E3%29+
Combine like terms in the numerator
+%28m%5E16x%5E14%29+%2F+%282m%5E3x%5E2%29+%283%5E3m%5E12x%5E3%29+
Work the coefficients in the denominator and combine like terms
+%28m%5E16x%5E14%29+%2F+%2854m%5E15x%5E5%29+
reduce the fraction by dividing (subtract powers)
+%28mx%5E9%29%2F54+





Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
By "solve" I expect you "simplify"
Simplify:

Now multiply the exponents inside the parenthese by the ones outside the parentheses.

Combine like-factors:
%282%5E%28-1%29%283%5E-3%29m%5E%28-15%29x%5E%28-5%29%29%2F%28m%5E-4%29x%5E%284%29
Remember that you can change the sign of the exponents by moving the factor down or up as the case maybe.
To simplify this expression, you want all the exponents to be positive.
%28m%5E4%29%2F%28%282%5E1%29%283%5E3%29m%5E15x%5E9%29
m%5E4%2F%282%2A27%2Am%5E15%28x%5E9%29%29+=+1%2F54m%5E11%28x%5E9%29