SOLUTION: add (7b+5b^2-3) + (3b^3-5b +8)=
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Question 742916
:
add
(7b+5b^2-3) + (3b^3-5b +8)=
Answer by
rfer(16322)
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7b+5b^2-3+3b^3-5b+8=
3b^3+5b^2+2b+5
(