SOLUTION: Factor Completely: x^3 - 2x^2 - 4x - 8 My answer: 2(-2x^3 - x^2 - 2x - 2^2) I am just learning the factoring process, so am not real sure of my answers. I have already att

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Factor Completely: x^3 - 2x^2 - 4x - 8 My answer: 2(-2x^3 - x^2 - 2x - 2^2) I am just learning the factoring process, so am not real sure of my answers. I have already att      Log On


   

Question 74230This question is from textbook Intermediate Algebra
: Factor Completely:
x^3 - 2x^2 - 4x - 8
My answer: 2(-2x^3 - x^2 - 2x - 2^2)
I am just learning the factoring process, so am not real sure of my answers. I have already attempted to work this problem, but not sure my answer is correct. could someone please review and assist me?
Milliron This question is from textbook Intermediate Algebra

Answer by rmromero(383) About Me  (Show Source):
You can put this solution on YOUR website!


Factor Completely:

x^3 - 2x^2 - 4x - 8



My answer: 2(-2x^3 - x^2 - 2x - 2^2) 





This is factoring by grouping

                  x^3 - 2x^2 - 4x - 8

                 (x^3 - 4x) + (-2x^2 - 8)

                 x(x^2 - 4) + (-2)(x^2 - 4)

                 x(x^2 - 4) - 2(x^2 - 4)

Factor out the common factor

                 (x^2 - 4)(x - 2)