SOLUTION: divide the following fraction.. 6 p - 1 8 over 9 p divided by 3 p - 9 over p ^ 2 + 2 p = 6 p - 1 8 over 9 p multiplied by p ^ 2 + 2 p over 3 p - 9 = 6 ( p - 3 ) over 3 (

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: divide the following fraction.. 6 p - 1 8 over 9 p divided by 3 p - 9 over p ^ 2 + 2 p = 6 p - 1 8 over 9 p multiplied by p ^ 2 + 2 p over 3 p - 9 = 6 ( p - 3 ) over 3 (       Log On


   

Question 72926: divide the following fraction..
6 p - 1 8 over 9 p divided by 3 p - 9 over p ^ 2 + 2 p =
6 p - 1 8 over 9 p multiplied by p ^ 2 + 2 p over 3 p - 9 =
6 ( p - 3 ) over 3 ( 3 p ) mulitplied by p ( p + 2 ) over 3 ( p - 3 )=
i know that i need to divide out the common factors :( p - 3 ), but after that is where i get stuck.
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+%28%286+p+-+1+8%29%2F%289+p%29%29%2F%28%283+p+-+9%29%2F%28p+%5E+2+%2B++2+p%29%29+
Before you begin factoring remember the following:
+%28a%2Fb%29%2F%28c%2Fd%29+=+ad%2Fbc+
Apply this to your problem
+%28%286p-18%29%28p%5E2%2B2p%29%29%2F%28%289p%29%283p-9%29%29+
Now factor
+%286p%28p-3%29%28p%2B2%29%29%2F%28%2827p%29%28p-3%29%29+
Cancel the (p-3)
+%286p%28p%2B2%29%29%2F%2827p%29+
reduce the 6p and the 27p by dividing by 3
+%282%28p%2B2%29%29%2F%289%29+
This is your final answer