SOLUTION: What is the y-intercept of y = 7/x + 2. What is the x-intercept?

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Question 710379: What is the y-intercept of y = 7/x + 2.
What is the x-intercept?

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
First of all, please put multiple-term numerators and denominators in parentheses. What you posted meant:
y+=+7%2Fx+%2B+2
But I don't this this is correct because this equation has no y-intercept. I'm going to work on the assumption that the equation is supposed to be:
y+=+7%2F%28x+%2B+2%29
which should be posted as: y = 7/(x + 2)
(If you're not sure what "multiple-term numerators and denominators" are, just put parentheses around all numerators and denominators.)

Y-intercepts are where a graph intersects the y-axis. All points on the y-axis have x coordinates of 0. So to find y-intercepts you make the x's in the equation zero and then solve for y:
y+=+7%2F%28%280%29+%2B+2%29
Simplifying we get:
y+=+7%2F2
So the y-intercept is: (0, 7/2)

X-intercepts are where a graph intersects the x-axis. All points on the x-axis have y coordinates of 0. So to find x-intercepts you make the y's in the equation zero and then solve for x:
0+=+7%2F%28x+%2B+2%29
You might already see a problem. If not, go ahead and solve for x. Multiplying each side by x+2 will eliminate the fraction:
0+=+7
Now we can see a problem. There are no x's left in the equation and we have an equation that is not true. This means that it is impossible for the y coordinate to be zero. This means that there is no x-intercept for the graph. This means that the graph never crosses (or touches) the x-axis. This means that the graph is entirely above or entirely below the x-axis. Since the y-intercept, (0, 7/2), is above the x-axis the graph is entirely above the x-axis.

P.S. If your equation really was:
y+=+7%2Fx+%2B+2
then you should now know how to find the intercepts.