SOLUTION: Suppose that the area of a circle is numerically equal to the perimeter of a square and that the length of a radius of the circle is equal to the length of a side of the square. Fi
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-> SOLUTION: Suppose that the area of a circle is numerically equal to the perimeter of a square and that the length of a radius of the circle is equal to the length of a side of the square. Fi
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Question 709592: Suppose that the area of a circle is numerically equal to the perimeter of a square and that the length of a radius of the circle is equal to the length of a side of the square. Find the length of a side of the square. Express your answer in terms of π. Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! Area of circle,, and there is a square of sidelength x.
, because as given, the perimeter of the square is numerically equal to the area of the circle. Then .
Given that r=x, we can now say by substitution, ,... .
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