SOLUTION: Divide x^3 + 2x^2 + x + 12/ x + 3 I am stuck: I got to this point and need some help.... x^3 + 2x^2 +x + 12 x^3 + 3x^2 _ x^2 +x + 12 _ x^2 -3x 4x +

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Divide x^3 + 2x^2 + x + 12/ x + 3 I am stuck: I got to this point and need some help.... x^3 + 2x^2 +x + 12 x^3 + 3x^2 _ x^2 +x + 12 _ x^2 -3x 4x +       Log On


   

Question 70823This question is from textbook Beginning Algebra
: Divide x^3 + 2x^2 + x + 12/ x + 3
I am stuck: I got to this point and need some help....
x^3 + 2x^2 +x + 12
x^3 + 3x^2
_ x^2 +x + 12
_ x^2 -3x
4x + 12

This is where I got stuck. Thanks for your help.
This question is from textbook Beginning Algebra

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
I'm not sure why you think you are stuck. You've done everything correctly up to this point.
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All you have to do now is divide 4x+%2B+12 by x%2B3. The answer is 4.
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This makes the complete answer to your problem x%5E2+-+x+%2B+4. To check this answer,
multiply it by x%2B3 and see if you don't get back to the original dividend of x%5E3%2B2x%5E2%2Bx%2B12.
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You seem to understand the division process. Good work!