SOLUTION: Use polynomial division to determine:
3x^3-5x^2+10x+4 / 3x+1
Any help would be appreciated I have not done these for years and cant get my head around them
Thanks
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Use polynomial division to determine:
3x^3-5x^2+10x+4 / 3x+1
Any help would be appreciated I have not done these for years and cant get my head around them
Thanks
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Question 699219: Use polynomial division to determine:
3x^3-5x^2+10x+4 / 3x+1
Any help would be appreciated I have not done these for years and cant get my head around them
Thanks Found 2 solutions by stanbon, pmatei:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Use polynomial division to determine:
3x^3-5x^2+10x+4 / 3x+1
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Divide the dividend by the divisor:
1st term of the quotient: x^2
----
Multiply times the divisor to get:
3x^3+x^2
----
Subtract from the dividend to get:
-6x^2+10x+4
----
Divide that dividend by the divisor:
2nd term of the quotient: -2x
===============
Multiply times the divisor to get:
-6x^2-2x
---
Subtract from the dividend to get:
12x+4
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Divide the dividend by the divisor to get
3rd term of the quotient: 4
====
Multiply times the divisor to get:
12x + 4
-----
Subtract from the dividend to get:
0
=====
Final Quotient: x^2 -2x + 4
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Cheers,
Stan H.
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You can put this solution on YOUR website! So your Numerator is and your Denominator is .
I will write this as a fraction, and explain how I get every term in the Quotient.
The first term of the Quotient is given by the division of the first term in Numerator by the first tern in the Denominator , which is
Then I multiply the term I just found with the Denominator and the result is subtracted from the Numerator to calculate the Remainder:
The Remainder is:
So I can write :
Now I do it again for the fraction
So now my quotient is
Do it one more time for fraction
So the final result is: