SOLUTION: I really am just lost on this problem. {{{t/(t-3) + 3/(t+3) = 18/ (t^2-9)}}} I thought I had to cancel out the denominators and I know that the denominator after the equal si

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I really am just lost on this problem. {{{t/(t-3) + 3/(t+3) = 18/ (t^2-9)}}} I thought I had to cancel out the denominators and I know that the denominator after the equal si      Log On


   



Question 676841: I really am just lost on this problem.
t%2F%28t-3%29+%2B+3%2F%28t%2B3%29+=+18%2F+%28t%5E2-9%29
I thought I had to cancel out the denominators and I know that the denominator after the equal sign is the equivalent of the two before it but I got so lost while trying to work out this problem

Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
%28t%2F%28t-3%29%29+%2B+%283%2F%28t%2B3%29%29+=+%2818%2F%28t%5E2-9%29%29
...
Multiply the entire equation by (t^2-9) which is (t-3)(t+3)
...
t%28t%2B3%29+%2B+3%28t-3%29+=+18
...
t%5E2+%2B+3t+%2B+3t+-+9+=+18
...
t%5E2+%2B+6t+-+9+-+18+=+0
...
t%5E2+%2B+6t+-27=0
...
(t-3)(t+9)=0
t = 3
t = -9
.....................
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