SOLUTION: how do i factor 6x^3 + 15x^2 + -9x

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Question 645131: how do i factor 6x^3 + 15x^2 + -9x
Found 3 solutions by jim_thompson5910, stanbon, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Note:

6x^3 + 15x^2 + -9x

is the same as

6x^3 + 15x^2 - 9x


6x%5E3%2B15x%5E2-9x Start with the given expression.


3x%282x%5E2%2B5x-3%29 Factor out the GCF 3x.


Now let's try to factor the inner expression 2x%5E2%2B5x-3


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Looking at the expression 2x%5E2%2B5x-3, we can see that the first coefficient is 2, the second coefficient is 5, and the last term is -3.


Now multiply the first coefficient 2 by the last term -3 to get %282%29%28-3%29=-6.


Now the question is: what two whole numbers multiply to -6 (the previous product) and add to the second coefficient 5?


To find these two numbers, we need to list all of the factors of -6 (the previous product).


Factors of -6:
1,2,3,6
-1,-2,-3,-6


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -6.
1*(-6) = -6
2*(-3) = -6
(-1)*(6) = -6
(-2)*(3) = -6

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 5:


First NumberSecond NumberSum
1-61+(-6)=-5
2-32+(-3)=-1
-16-1+6=5
-23-2+3=1



From the table, we can see that the two numbers -1 and 6 add to 5 (the middle coefficient).


So the two numbers -1 and 6 both multiply to -6 and add to 5


Now replace the middle term 5x with -x%2B6x. Remember, -1 and 6 add to 5. So this shows us that -x%2B6x=5x.


2x%5E2%2Bhighlight%28-x%2B6x%29-3 Replace the second term 5x with -x%2B6x.


%282x%5E2-x%29%2B%286x-3%29 Group the terms into two pairs.


x%282x-1%29%2B%286x-3%29 Factor out the GCF x from the first group.


x%282x-1%29%2B3%282x-1%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B3%29%282x-1%29 Combine like terms. Or factor out the common term 2x-1


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So 3x%282x%5E2%2B5x-3%29 then factors further to 3x%28x%2B3%29%282x-1%29


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Answer:


So 6x%5E3%2B15x%5E2-9x completely factors to 3x%28x%2B3%29%282x-1%29.


In other words, 6x%5E3%2B15x%5E2-9x=3x%28x%2B3%29%282x-1%29 for all values of x.


Note: you can check the answer by expanding 3x%28x%2B3%29%282x-1%29 to get 6x%5E3%2B15x%5E2-9x or by graphing the original expression and the answer (the two graphs should be identical).

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Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
factor 6x^3 + 15x^2 + -9x
-------
= 3x(2x^2 + 5x -3)
---
= 3x(2x^2 -x+6x -3)
------
= 3x(x(2x-1)+3(2x-1))
----
= 3x(2x-1)(x+3)
=====================
Cheers,
Stan H.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

6x%5E3+%2B+15x%5E2+-9x.......replace 15x%5E2 with -3x%5E2+%2B18x%5E2
6x%5E3++-3x%5E2+%2B18x%5E2-9x...group
%286x%5E3+-3x%5E2%29+%2B%2818x%5E2-9x%29
6x%5E2%282x+-1%29+%2B9x%282x-1%29
%286x%5E2+%2B9x%29%282x-1%29
3x%282x+%2B3%29%282x-1%29