SOLUTION: solve for k in k/k+1=3/k^2-k-2 a. k=3 b/ k=-1 and k=2 c. k=-1 and k=3 d. k=-1 can you please show me how to do this, ty

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: solve for k in k/k+1=3/k^2-k-2 a. k=3 b/ k=-1 and k=2 c. k=-1 and k=3 d. k=-1 can you please show me how to do this, ty      Log On


   

Question 634073: solve for k in k/k+1=3/k^2-k-2
a. k=3
b/ k=-1 and k=2
c. k=-1 and k=3
d. k=-1
can you please show me how to do this, ty
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
I will assume that you mean
k/(k+1)=3/(k^2-k-2)
k=3 only because k = -1 would make the denominator zero.