SOLUTION: I seem to be stuck with this problem: 2x(squared)-18=0 (I Can't put the squared signed next to the 2x) I am not sure on how to factor this: I tried x(2x-18)=0 Is that corr

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I seem to be stuck with this problem: 2x(squared)-18=0 (I Can't put the squared signed next to the 2x) I am not sure on how to factor this: I tried x(2x-18)=0 Is that corr      Log On


   



Question 63297: I seem to be stuck with this problem:
2x(squared)-18=0 (I Can't put the squared signed next to the 2x)
I am not sure on how to factor this:
I tried x(2x-18)=0 Is that correct?

Found 2 solutions by jai_kos, funmath:
Answer by jai_kos(139) About Me  (Show Source):
You can put this solution on YOUR website!
Given 2x^2 - 18 = 0
Add 18 on both sides, we get
2x^2 -18 +18 = 0 +18
2x^2 = 18
Divide by 2, we get
2x^2 / 2 = 18 /2
x^2 = 9
Take the square root,
we get sqrt(x^2) = sqrt(9)
x = + 3 or -3
Whenever we take the square root, we get two values one with positive sign and one with negative sign.

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2-18=0
2%28x%5E2-9%29=0
2%28x%5E2-9%29%2F2=0%2F2
x%5E2-9=0
%28x%2B3%29%28x-3%29=0
x+3=0 and x-3=0
x+3-3=0-3 and x-3+3=0+3
x=-3 and x=3
Happy Calculating!!!!