SOLUTION: Have I done this problem correctly? (q+3/4)(q+3/4)= q^2+3/4q+9/16

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Question 631646: Have I done this problem correctly?
(q+3/4)(q+3/4)= q^2+3/4q+9/16
Found 2 solutions by Maths68, jim_thompson5910:
Answer by Maths68(1474) (Show Source):
You can put this solution on YOUR website!
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Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
$\left(q+\frac{3}{4}\right)\left(q+\frac{3}{4}\right)$

$q*q+\frac{3}{4}q+\frac{3}{4}q+\left(\frac{3}{4}\right)\left(\frac{3}{4}\right)$

$q^2+\frac{3}{4}q+\frac{3}{4}q+\frac{9}{16}$

$q^2+\frac{6}{4}q+\frac{9}{16}$

$q^2+\frac{3}{2}q+\frac{9}{16}$

So $\left(q+\frac{3}{4}\right)\left(q+\frac{3}{4}\right) = q^2+\frac{3}{2}q+\frac{9}{16}$

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