SOLUTION: Given that f(x) has real coefficients and x=k is a zero, what other number must be a zero? Have no idea how to go about this. Please help me. k=3- {{{ sqrt(2) }}} k=1+i {{{ s

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Given that f(x) has real coefficients and x=k is a zero, what other number must be a zero? Have no idea how to go about this. Please help me. k=3- {{{ sqrt(2) }}} k=1+i {{{ s      Log On


   



Question 627090: Given that f(x) has real coefficients and x=k is a zero, what other number must be a zero? Have no idea how to go about this. Please help me.
k=3- +sqrt%282%29+
k=1+i +sqrt%285%29+
k= +sqrt%282%29 + i +sqrt%287%29+
k=i

Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Your problem statement is incomplete.
Cheers,
Stan H.
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Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Both irrational and complex roots come in conjugate pairs given a polynomial equation with real coefficients.

If you have an irrational root of the form , then must also be a root. If you have a complex root of the form , then must also be a root. Hint:

John

My calculator said it, I believe it, that settles it
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