SOLUTION: The heat loss H, in watts, through a single-pane glass window varies jointly as the area A, in square meters, and the difference between the inside and outside temperatures T, in d

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The heat loss H, in watts, through a single-pane glass window varies jointly as the area A, in square meters, and the difference between the inside and outside temperatures T, in d      Log On


   



Question 620448: The heat loss H, in watts, through a single-pane glass window varies jointly as the area A, in square meters, and the difference between the inside and outside temperatures T, in degrees Celsius. If the heat loss is 6 watts for a window with an area of 1.5 m^2 and a temperature difference of 2 degrees Celcius, what would be the heat loss for a window with an area of 2 m^2 and a temperature difference of 5 degrees Celcius?
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi,
The heat loss H, in watts, through a single-pane glass window varies jointly as
the area A, in square meters, and the difference between the inside and
outside temperatures T, in degrees Celsius H%0D%0A++=+kAT%5Bdiff%5D
If the heat loss is 6 watts for a window with an area of 1.5 m^2 and a
temperature difference of 2 degrees Celcius, 6+=+1.5%2A2%2Ak k = 2
what would be the heat loss for a window with an area of 2 m^2 and a temperature
difference of 5 degrees Celcius? H+=+2A%2At%5Bdiff%5D=+2%2A2%2A5+=+20watts