SOLUTION: Please help me. Find the x intercepts of the graphof each equation y=4x^2+5x-6 I know I set y to=0 beyond that I'm stuck Thank you

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Please help me. Find the x intercepts of the graphof each equation y=4x^2+5x-6 I know I set y to=0 beyond that I'm stuck Thank you      Log On


   

Question 60923: Please help me.
Find the x intercepts of the graphof each equation
y=4x^2+5x-6
I know I set y to=0 beyond that I'm stuck

Thank you
Answer by joyofmath(189) About Me  (Show Source):
You can put this solution on YOUR website!
You are solving a quadratic equation here.
4x%5E2%2B5x-6+=+0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ with a=4 b=5 c=-6
Then, x+=+%28-5+%2B-+sqrt%285%5E2-4%284%29%28-6%29%29%29%2F%282%2A4%29
Or, x+=+%28-5+%2B-+sqrt%2825%2B16%2A6%29%29%2F8
Or, x+=+%28-5+%2B-+sqrt%28121%29%29%2F8
Or, x+=+%28-5+%2B-+11%29%2F8
Or, x+=+-16%2F8+=+-2 and x+=+6%2F8+=+3%2F4
Verify these values in the original equation:
4%28%28-2%29%5E2%29%2B5%28-2%29-6+=+4%2A4-10-6 which is indeed 0.