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Question 60765This question is from textbook intermediate algebra
: Can u help me sove this problem. Its from the rational expressions, equations , and functions chapter of my book.
6/2x^2-4x+3-1/x-3=1/4x-4
This question is from textbook intermediate algebra
Answer by Edwin McCravy(20054)   (Show Source):
You can put this solution on YOUR website! Can u help me sove this problem. Its from the rational expressions,
equations , and functions chapter of my book.
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Sorry, but we cannot make heads or tails of
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6/2x^2-4x+3-1/x-3=1/4x-4
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When typing fractional equations and expressions all on one line,
you MUST enclose numerators and denominators inside parentheses
which contain more than just one number or just one letter.
so we can tell where they begin and where they end.
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Do you mean this?:
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6/(2x^2-4x+3) - 1/(x-3) = 1/(4x-4)
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or this
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6/(2x^2-4x) + 3 - 1/x - 3 = 1/(4x) - 4
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or this
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6/(2x^2) - (4x+3) - 1/(x-3) = 1/(4x-4)
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or this
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[6/(2x)]^2 - 4x + (3-1)/x - 3 = 1/(4x-4)
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or many many more possibilities? Please repost
with parentheses around each numerator and denominator
that cantains more than one letter or one number so
we can tell where the numerators and denominators
stop and end.
Edwin
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