SOLUTION: Hey!..can u please help me with this problem?..it has to be factored completely. 8b^2+12b+4 thanks!

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hey!..can u please help me with this problem?..it has to be factored completely. 8b^2+12b+4 thanks!      Log On


   

Question 60705: Hey!..can u please help me with this problem?..it has to be factored completely.
8b^2+12b+4
thanks!
Found 2 solutions by checkley71, funmath:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
8B^2+12B+4=0
2B^2+3B+1=0
(2B+1)(B+1)=0
2B+1=0
2B=-1
B=-1/2 SOLUTION
B+1=0
B=-1 SOLUTION

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
factor completely.
8b%5E2%2B12b%2B4
4%282b%5E2%2B3b%2B1%29 2b*b=2b^2 and 1*1=1 and 2b*1+b*1=3b, so
4%282b%2B1%29%28b%2B1%29
Happy Calculating!!!