Question 60411This question is from textbook
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Divide (2x^3+3x^2-3X+4) By (x+2)
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This question is from textbook
Answer by smik(40)   (Show Source):
You can put this solution on YOUR website! Well, here's a short cut that works when you're dividing two polynomials where one is a linear expression, as is (x+2). The zero value, or the value of x that would give us zero for the expression, for (x+2) would be (-2). So, what we do is we line up the -2 on the left, which should be followed by the coefficients. Hence we have the following:
-2 ||....2...3...-3...4
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.............2..-1...-1...6
In the above, we brought the two down. Then we multiplied this by (-2) which gives us -4. We add 3 and -4, which gives us -1. Then -1 is multiplied with -2, which gives us 2. This 2 is added to -3, which gives us -1. -2 is then multiplied to -1, which gives us 2. This 2 is added to 4 which gives us 6.
Now all we have to do is bring back the 'x' values and reduce the degree by 1, so we get:
Hope this helped and wasn't too confusing. If it was, go to:
www.purplemath.com/modules/polydiv2.htm for further help.
They use a clearer method which works for more cases then the above.
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