SOLUTION: I don't know how to solve for the area of a triangle with a height of 5xsqrt and a base of 10x to the sixth power.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I don't know how to solve for the area of a triangle with a height of 5xsqrt and a base of 10x to the sixth power.      Log On


   

Question 603206: I don't know how to solve for the area of a triangle with a height of 5xsqrt and a base of 10x to the sixth power.
Answer by KMST(5347) About Me  (Show Source):
You can put this solution on YOUR website!
NOTE:
I may be misinterpreting "5xsqrt" and or "10x to the sixth power"
The conventional way to type square roots and powers is like this:
sqrt%28x%29=sqrt(x) , 10x%5E6=10%2Ax%5E6=10x^6=10*x^6 , and %2810x%29%5E6=(10x)^6
We use ^ to indicate that the exponent is written higher than the rest; we use * to indicate multiplication, and we use sqrt( ) when we mean square root, with whatever is under the radical sign in the brackets.

IF THE PROBLEM WAS base=10x%5E6 and height=5sqrt%28x%29
You must know that the area of a triangle can be calculated as 1/2 times base, times height.
area=%281%2F2%29%2810x%5E6%29%285sqrt%28x%29%29
That can be simplified somewhat.
Because of the associative and commutative properties, numbers and expressions that are multiplied together can be multiplied in any order, grouping them in any way, with the same result.
You have 1%2F2 10 x%5E6 5 and sqrt%28x%29 multiplied together, grouped by brackets in a certain way. The resulting product is the same if the grouping and order is changed to a more convenient way:

So area=%28%281%2F2%29%2A10%2A5%29%28x%5E6%2Asqrt%28x%29%29
We can do the indicated multiplication, and there are different ways to express it, but I like
area=25x%5E6%2Asqrt%28x%29 or the same thing without the dot between x%5E6 and sqrt%28x%29.

IF THE PROBLEM WAS base=%2810x%29%5E6 and height=5sqrt%28x%29
you must know that %2810x%29%5E6=10%5E6%2Ax%5E6=1000000x%5E6
but the rest of the calculation is done in a similar way.