SOLUTION: the length of a rectangle is 2 cm greater than twice its width. The area of the rectangle is 40 cm^2. find the dimensions of the rectangle.
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-> SOLUTION: the length of a rectangle is 2 cm greater than twice its width. The area of the rectangle is 40 cm^2. find the dimensions of the rectangle.
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Question 597503: the length of a rectangle is 2 cm greater than twice its width. The area of the rectangle is 40 cm^2. find the dimensions of the rectangle. Answer by ExplanationCentral(10) (Show Source):
You can put this solution on YOUR website! Let the length be l and the width be w.
So we have l = 2w + 2.
The area of the rectangle = length*width = (2w+2)*w = 2w^2 + 2w = 40
Solving this quadratic equation, we get w = 4 cm. This means the length = 2(4) + 2 = 10.
So width = 4 and length = 10.
