SOLUTION: okay so thequestion sais what is the degree of 6/t^3−9t^5+3 i figured the leading coefficient was -9 and thedreaag was 5 but it said that was wrong so i tried to factor out T

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: okay so thequestion sais what is the degree of 6/t^3−9t^5+3 i figured the leading coefficient was -9 and thedreaag was 5 but it said that was wrong so i tried to factor out T      Log On


   

Question 541161: okay so thequestion sais what is the degree of 6/t^3−9t^5+3 i figured the leading coefficient was -9 and thedreaag was 5 but it said that was wrong so i tried to factor out T63 by moving theothernumbersto the other side and getting 6/t^3 alone and crossmultiply to get a degree of 8 but that also did not help. so I am stuck now
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
6%2Ft%5E3-9t%5E5%2B3 (as you wrote it) is not a polynomial.
Just in case, 6%2F%28t%5E3-9t%5E5%2B3%29 is not a polynomial either.
(Negative exponents and variables in denominators are not allowed in polynomials).
So degree is not defined for such expressions.
As you wrote it, there is no equal sign, so there is no "other side."
If it were polynomial 6t%5E3-9t%5E5%2B3, the leading coefficient would be -9 and the degree would be 5, like you thought.
y=6%2F%28t%5E3-9t%5E5%2B3%29 and y=6%2Ft%5E3-9t%5E5%2B3 are rational functions.
My guess is that you are taking an online course, and someone messed up when entering the questions and answers. As one of my sons attended an online charter school, I am familiar with that phenomenon. (I assume that typos happen in printed problems given to students in brick-and-mortar schools, too, but I could not see every mistake that happened in school when my children attended them).