SOLUTION: Factor completely: {{{(x+1)^3 * x - 2(x+1)^2 * x^2 + x^3(x+1)}}}
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-> SOLUTION: Factor completely: {{{(x+1)^3 * x - 2(x+1)^2 * x^2 + x^3(x+1)}}}
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Question 540953
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Factor completely:
Answer by
Theo(13342)
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if we replace (x+1) with a, then we get:
we can factor out an x and an a to get:
we can factor
to get:
we now replace a with (x+1) to get: