SOLUTION: I am supposed to find the imaginary solution to the following equation and check my answer. 9x^2-6x+4=0 So far I have: x=(6+/- sqrt(6)^2-4(9)(4))/18 x=(6+/- sqrt-108)/18 x= (6

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am supposed to find the imaginary solution to the following equation and check my answer. 9x^2-6x+4=0 So far I have: x=(6+/- sqrt(6)^2-4(9)(4))/18 x=(6+/- sqrt-108)/18 x= (6      Log On


   

Question 53808This question is from textbook
: I am supposed to find the imaginary solution to the following equation and check my answer. 9x^2-6x+4=0 So far I have:
x=(6+/- sqrt(6)^2-4(9)(4))/18
x=(6+/- sqrt-108)/18
x= (6+/- 6i sqrt3)/18
x=(1+/- i sqrt3)/3
This does not check where did I go wrong?
This question is from textbook

Answer by anjulasahay(30) About Me  (Show Source):
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I am supposed to find the imaginary solution to the following equation and check my answer. 9x^2-6x+4=0 So far I have:
x=(6+/- sqrt(6)^2-4(9)(4))/18
x=(6+/- sqrt-108)/18
x= (6+/- 6i sqrt3)/18
x=(1+/- i sqrt3)/3
This does not check where did I go wrong?
solun: 9x^2-6x+4 = 0
x = (-(-6)+ - sqrt((-6)^2-4*9*4))/(2*9)
= (6 + - sqrt(36 - 4 * 36 ))/18
= (6 + - (6 * (sqrt(-3))))/18 since sqrt(-1) = i
= (1+i sqrt(3)/3 or 3(1-i sqrt(3))/3 hence sqrt(-3) = i sqrt(3)