SOLUTION: Solve and graph the equations x/5 - y/3 = 1 x/2 + y/7 = 0 x= y= equation 1 x-axis intercept= equation 1 y-axis intercept= equation 2 x-axis intercept= equation 2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Solve and graph the equations x/5 - y/3 = 1 x/2 + y/7 = 0 x= y= equation 1 x-axis intercept= equation 1 y-axis intercept= equation 2 x-axis intercept= equation 2       Log On


   



Question 49150: Solve and graph the equations
x/5 - y/3 = 1
x/2 + y/7 = 0
x=
y=
equation 1 x-axis intercept=
equation 1 y-axis intercept=
equation 2 x-axis intercept=
equation 2 y-axis intercept=

Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
To find the y-axis intercept, let x = 0 and solve for y
To find the x-axis intercept, let y = 0 and solve for x
.
x/5 - y/3 = 1 [Let x = 0]
0/5-y/3=1[Solve for y]
0-y/3=1
-y/3=1
(-3)(-y)/3=(-3)(1)
y=-3
Plot point (0, -3)
equation 1 y-axis intercept= (0, -3)
.
x/5 - y/3 = 1 [Let y = 0]
x/5 - (0)/3 = 1 [Solve for x]
x/5 - 0 = 1
x/5 = 1
(5)(x/5) = (5)(1)
x=5
Plot point (5, 0)
equation 1 x-axis intercept = (5, 0)
.
.
x/2 + y/7 = 0 [Let x = 0]
(0)/2 + y/7 = 0 [Solve for y]
0 + y/7=0
y/7 = 0
(7)(y/7)=(7)(0)
y=0
Plot point (0, 0)
Since this is not enough to plot the graph, plug-in other values for x or y and solve for x or y. Plot these additionals points (-2, 7) (-4, 14) (2, -7)(4,-14)
equation 2 y-axis intercept= (0, 0)
.
x/2 + y/7 = 0 [Let y=0]
x/2 + (0)/7 = 0 [Solve for x]
x/2 + 0 = 0
x/2 = 0
(2)(x/2) = (2)(0)
x=0
Plot point (0, 0)
equation 2 x-axis intercept= (0, 0)
.
.
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