SOLUTION: 4m/m-3 + 6/3-m = m (Please help!)

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Question 49006: 4m/m-3 + 6/3-m = m (Please help!)
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
4m%2F%28m-3%29+%2B+6%2F%283-m%29+=+m Rewrite the second term on the left side as: -6%2F%28m-3%29
4m%2F%28m-3%29+-+6%2F%28m-3%29+=+m Add the fractions on the left side. The common denominator is (m-3).
%284m-6%29%2F%28m-3%29+=+m Multiply both sides by (m-3).
4m-6+=+m%28m-3%29 Simplify this.
4m-6+=+m%5E2-3m Subtract 4m from both sides.
-6+=+m%5E2-7m Add 6 to both sides.
m%5E2-7n%2B6+=+0 Solve this quadratic equation by factoring.
%28m-1%29%28m-6%29+=+0 Apply the zero product principle.
m-1+=+0 and/or m-6+=+0
If m-1+=+0 then m+=+1
If m-6+=+0 them mm+=+6
Solutions:
m = 1
m = 6
You can check the solutions by substituting them, one-at-a-time into the original equation.