SOLUTION: I have to use the binomial theorem to find the 9th term of (a/b + b/a)^11 instead of expanding the whole thing out. I got as far as 165*(a/b)^3*(b/a)^8 but am not sure about simpli
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-> SOLUTION: I have to use the binomial theorem to find the 9th term of (a/b + b/a)^11 instead of expanding the whole thing out. I got as far as 165*(a/b)^3*(b/a)^8 but am not sure about simpli
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Question 464568: I have to use the binomial theorem to find the 9th term of (a/b + b/a)^11 instead of expanding the whole thing out. I got as far as 165*(a/b)^3*(b/a)^8 but am not sure about simplifying the fractions (I have always struggled with fractions). Is the answer I gave enough or do I need to go further, and if so, please help! Answer by sudhanshu_kmr(1152) (Show Source):
