SOLUTION: How to factor {{{x^3-x^2+8x-8}}} completely? So far I have this as my work... {{{x^3-x^2+8x-8}}} {{{(x^3-x^2)*(8x-8)}}} {{{x^2(x-1)+8(x-1)}}} {{{(x-1)*(x^2+8)}}} I'm n

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How to factor {{{x^3-x^2+8x-8}}} completely? So far I have this as my work... {{{x^3-x^2+8x-8}}} {{{(x^3-x^2)*(8x-8)}}} {{{x^2(x-1)+8(x-1)}}} {{{(x-1)*(x^2+8)}}} I'm n      Log On


   

Question 442964: How to factor x%5E3-x%5E2%2B8x-8 completely?
So far I have this as my work...
x%5E3-x%5E2%2B8x-8
%28x%5E3-x%5E2%29%2A%288x-8%29
x%5E2%28x-1%29%2B8%28x-1%29
%28x-1%29%2A%28x%5E2%2B8%29
I'm not sure what else to do after that, how do I get rid of the x%5E2 at the end there?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
So far I have this as my work...
x%5E3-x%5E2%2B8x-8
x%5E2%28x-1%29+%2B+8%28x-1%29
= %28x%5E2%2B8%29%28x-1%29
That's it.
--------------
%28x%5E3-x%5E2%29%2A%288x-8%29
x%5E2%28x-1%29%2B8%28x-1%29
%28x-1%29%2A%28x%5E2%2B8%29
I'm not sure what else to do after that, how do I get rid of the x%5E2 at the end there?