SOLUTION: y varies directly with the sqquare of x and inversely with z. If y=16 when x=2 and z=3, find k, the constant of proportionality, and find y when x=5 and z=4

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: y varies directly with the sqquare of x and inversely with z. If y=16 when x=2 and z=3, find k, the constant of proportionality, and find y when x=5 and z=4      Log On


   



Question 441668: y varies directly with the sqquare of x and inversely with z. If y=16 when x=2 and z=3, find k, the constant of proportionality, and find y when x=5 and z=4
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+%28kx%5E2%29%2Fz
==> 16+=+%28k2%5E2%29%2F3 ==> 16 = 4k/3 ==> k = 12
==> y+=+%2812x%5E2%29%2Fz
==> y+=+%2812%2A25%29%2F4+=+3%2A25+=+75