SOLUTION: what are the roots of the polynomial F(x) = 3x^2 - 13x + 4

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Question 434712: what are the roots of the polynomial F(x) = 3x^2 - 13x + 4
Found 2 solutions by solver91311, MathLover1:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




The roots are the values of that make the value of the function equal zero.



The trinomial factors:



Just use the Zero Product Rule.


John

My calculator said it, I believe it, that settles it
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Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
F%28x%29+=+3x%5E2+-13x+%2B+4....use quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+...notice that a=3, b=-13 and c=4
x+=+%28-%28-13%29+%2B-+sqrt%28%28-13%29%5E2-4%2A3%2A4+%29%29%2F%282%2A3%29+
x+=+%2813+%2B-+sqrt%28169+-48+%29%29%2F6+
x+=+%2813+%2B-+sqrt%28121+%29%29%2F6+
x+=+%2813+%2B-+11+%29%2F6+
x1+=+%2813+%2B+11+%29%2F6+
x1+=+24%2F6+
x1+=+4
x2+=+%2813-+11+%29%2F6+
x2+=+2%2F6+
x2+=+1%2F3

let's see it on a graph

+graph%28+500%2C+500%2C+-10%2C15%2C+-15%2C+10%2C3x%5E2+-13x+%2B4%29+