SOLUTION: Hi. I am having a difficult time trying to figure out of to factor the trinomial. If you could help, that would be greatly appreciated.
2a^2 + 30a + 100. Thanks so much.
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Polynomials-and-rational-expressions
-> SOLUTION: Hi. I am having a difficult time trying to figure out of to factor the trinomial. If you could help, that would be greatly appreciated.
2a^2 + 30a + 100. Thanks so much.
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Question 425969: Hi. I am having a difficult time trying to figure out of to factor the trinomial. If you could help, that would be greatly appreciated.
2a^2 + 30a + 100. Thanks so much. Found 2 solutions by nerdybill, Theo:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! 2a^2 + 30a + 100
Start by factoring out what is common among all three terms:
2(a^2 + 15a + 50)
now, factor what is in the parenthesis:
2(a+5)(a+10)
looking at each of these and adding the 2 factors together you get:
1 + 50 = 51
2 + 26 = 26
5 + 10 = 15
factors of 5 and 10 look interesting because 5*10 = 50 and 5+10 = 15.
your factors could very well be:
(a + 5) * (a + 10) = 0
multiply these 2 factors together to get a^2 + 10a + 5a + 50 = 0
combine like terms to get a^2 + 15a + 50 = 0
these are your factors.
to get back to the original equation, multiply both sides of this equation by 2 to get 2a^2 + 30a + 100.
the basic procedure in factoring a quadratic equation is to get the equation into standard form and then to reduce it to the lowest possible common factors.
your expression was 2a^2 + 30a + 100.
place it into standard form by setting it equal to 0 to get:
2a^2 + 30a + 100 = 0
factor out to 2 to reduce it as much as possible to get:
a^2 + 15a + 50 = 0
etc. as we did above.
your factors came out to be (x+5) * (x+10) = 0
this equation is true if (x+5) = 0 or if (x+10) = 0.
